This I do, can not charge for the mobile phone interference, voltage and current can meet, 34063 circuit I also do, small current charging slow maximum 500 ma.
The charger is a regulated power supply, 5V400mA power supply. The battery is 7V4300mAh lithiumPool, full voltage 2V. Charging may damage the charger, because the battery is low, the regulator 5V is not enough, will damage the charger. If it is a 5V charging base output charging, you can use a 5V charger to connect to the base, the base limits the battery voltage.
Volt lithium battery charging limit voltage is 2 volts, can not use five volts power supply. You need a protection plate or a pressure reduction plate for the battery to use. And the 5 volt voltage is mostly constant voltage power supply, no constant current function, not suitable for charging the battery, easy to overload and burn.
Using 7V lithium battery input, output voltage 5V, output current up to 100Current 2A, module can also '> seek 18650 battery boost to 5V IC recommended, current 2A, module can also
1, FS4059D is a 5V input, support four lithium battery boost charge management IC. FS4059D built-in MOS tube, the use of asynchronous switching architecture, so that it needs only a few peripheral devices in the application, can effectively reduce the overall scheme size, reduce the BOM cost.
2, four 18650 batteries in parallel, its voltage can only be 7V, if the output current is required 2A, continuous discharge time is more thanShorter, therefore, with this battery as a power supply, the power of the electrical appliance can not be large, the working current must be less than 1A.
3, this is 1-2A booster circuit, for lithium battery charging is enough, you can also use the following: nothing easy to make, hope to help you, please adopt.
1. Method/Step 1B628 (PL2628) Output voltage Setting: VOUT=0.6× (1 R1/R2). Can passChange the R1 and R2 resistors of the third pin of the IC to change the output voltage. R1 is: resistance connected to the output end; R2: It's the resistance to the ground.
2, FSB628 (B6288Y) is a widely used in mobile power supply and other lithium battery boost 5V1A product chip. Next look at the inductance, capacitance and output voltage Settings of the selected B628 (B6288Y) boost IC. Screen printing of B6288Y: B628.
3, the foot is a multi-functional pin, and the second sound medium frequency signal under various standards can be unbalanced. Low voltage can be boosted. r1 or r2 can be used as an adjustable booster with adjustable resistors. If it is a fixed resistor it can be used as a fixed booster.
USB can use LMS1585 to power the MCU, but your lithium battery to power the MCU is more troublesome, because the lithium battery is fully charged to 2V, and the power can be 7V when the power is low, so it can not directly supply the MCU, but the general step-down IC can not work under such a low voltage difference.
MCU and peripheral chips are generally CMOS, the power supply voltage adaptation range is very wide, you have what reasonBe sure to work 3V, be more specific, there may be other solutions. And the voltage regulator is certainly not possible, the voltage regulator in front of the series to adjust the resistance, it is not as good as the low voltage difference regulator block.
Then there are a large number of corresponding chips, products and designs. This is what is called the "de facto standard". If you use a different voltage (such as 4V), there will be trouble in level switching when connecting with other circuits. For example, you can find a lot of 3V or 5V power chips, and almost no 4V power chips.
Its kernel is Cortex-M3. The series of chips press Fl on chipP dissipation, or output diffusion improvement.
1, if you really use the 7V battery is not a problem, because the boost generally has a Schottky, 7V battery will pass through the Schottky buck to the LED at this time the voltage added to the LED end is 4V-5V. Leds are bearable.
2, with No. 5 battery 5V, you can make the LED lamp work normally. No more thanUse mobile phone lithium battery 7V, easy to charge, large capacity, high voltage, no need to boost voltage, simple to use. Rechargeable LED flashlights are plentiful and cheap.
3, professional solution 1: the dry battery can not light the LED, the dry battery is 5V, and this LED is a series connection method, requiring a voltage of 220V. 2: If you do not want to use dry batteries, 146 dry batteries can be connected together, and then connected to the LED can be lit, but pay attention to the positive and negative poles.
To increase the DC voltage, it is necessary to use a switching circuit to change DC into high-frequency AC, and use a high-frequency transformer to boost and recirculate DC. Or as I said above, buy a DC voltage converter.
This I do, can not charge for the mobile phone interference, voltage and current can meet, 34063 circuit I also do a small current charging slow maximum 500 ma.
Self-made circuit diagram is shown in the figure. If there is an error in the voltage, the ratio of R3 to R4 can be fine-tuned.
The most efficientIt's DCDC. STM32F series belongs to the low-end 32-bit ARM microcontroller, the series chip is produced by ST company, its core is Cortex-M3.
It is best to use TI (Texas Instruments) booster charge pump device TPS60110, its peripheral components only need four small capacitors (2μF two, 15μF one, 33μF one., the voltage can be 10V).
Low efficiency, why reduce pressure and then increase pressure? 7V lithium boost voltage 5V can be. Other effects should be minor. It's like, you're trying toIt is also possible to use a lithium battery to output 3V and 5V at the same time, which has no impact, and consider the battery power supply capacity.